beta hexoaminadase is made up of an alpha and beta subunit. taysachs disease is due to a mutation in the alpha subunit gene, and sandhoff is due to a mutation in the beta subunit gene. if a carrier of taysachs disease marries a carrier of sandhoff disease what is the probablity that their first child will have either disease?

a. 0 %

b. 12.5%

c. 25%

d. 100%

keep in mind that i dont have the answers to the question so if u do answer please explain how u got the answer that u came up with. thanks guys...God bless

It's 0%, I think...

Tay Sachs: aA x aa = 50% carrier, 50% healthy
Sandhoff: bb X bB = 50% carriers, 50% healthy
Both ds are AR.

Each condition is considered separately. Since they are AR, the chance of having a child with either dz is 0.

Wrong!

a Taysach carrier (Tt) marries a sandhoff carrier (Ss) will produce TS, Ts, tS, st. In order to have a kid that has either disease, he/she would be tt or ss
. However, if this two people get married, they wont not produce tt or ss
so the answer is 0%

oops typo.. it should be they will NOT produce tt or ss..

hey unregistered we got the point but when you try to get you point across try to be a little nicer about it you all have a great day. God bless you all...and good luck studying