Renal Q , Please explain

[Anonymous]

A 35 yr old man complains of foamy urine.The following data are obtained from the pt:

Inulin clearence =100ml/min
Plasma osmolarity =286mOsm/L
Plasma Sodium concetration =140mEq/LUrine flow rate =1.44L/24hours
Urine Osmolarity=205mOsm/L
Urine Sodium Concetration =100mEq/L
Urine flow=1.44L/24hours

How much does this patient reabsorb Sodium everyday?

Will you please kindly calculate and give the answer? :wink: needs calculations first more than options
8) Thanks

[Anonymous]

Q: how much Na is reabsorbed?

A:
1. amount reabsorbed = amount filtered - amount excreted

1a. amount filtered = plasma conc * GFR

1ai. GFR = inulin = 100 mL/min

1aii. plasma conc = 140 mEq/L

Therefore: amount filtered = 20160mEq/day
(140 mEq/L * 1L/1000mL) * (100mL/min * 1440min/day)

1b. amount excreted = urine Na conc * urine flow rate

1bi. urine Na conc = 100 mEq/L

1bii. urine flow rate = 1.44 L/day

Therefore: amount excreted = 144 mEq/day
100 mEq/L * 1.44 L/day

2. Therefore, the amount reabsorbed = amount filtered - amount excreted

= 20160 mEq/day - 144 mEq/day = 20,016 mEq/day (normal)

[Anonymous]

1a. amount filtered = plasma conc * GFR

1ai. GFR = inulin = 100 mL/min

1aii. plasma conc = 140 mEq/L

Therefore: amount filtered = 20160mEq/day
(140 mEq/L * 1L/1000mL) * (100mL/min * 1440min/day)

I saw only 140 meg/L and 100 ml/min.
Please explain where other # came from. (1L/1000mL and 1440min/day). Thanks.

[Anonymous]

those numbers are standard:
there are 1000 mL in 1 L = 1L/1000mL

there are 60 min in 1 hr, 24 hrs in day = 1440 min/day